the length breadth and height of a room are 8 m 25 cm,6 m 75 cm and 4 m 50 cm,respectively.Determine the longest tape which can measure the three dimensions o the room.
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Answered by
19
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Length of the room = 8.25 m or 825 cm
Breadth of the room = 6.75 m = 675 cm
Height of the room = 4.50 m = 450 cm
We have to find the longest rod that can measure the three dimensions of the room exactly. For this, we have to find the Highest Common Factor of 825, 675 and 450.
Prime factorization of 825 = 3×5×5×11
Prime factorization of 675 = 3×3×3×5×5
Prime factorization = 450 = 2×3×3×5×5
Common factors = 3×5×5
H.C.F. = 75
Hence, H.C.F. of 825, 675 and 450 is 75
The length of the longest rod is 75 cm which can measure the three dimensions of the room exactly.
_________________________
HOPE , IT HELPS ... ✌️
_______________________
_______________________
Length of the room = 8.25 m or 825 cm
Breadth of the room = 6.75 m = 675 cm
Height of the room = 4.50 m = 450 cm
We have to find the longest rod that can measure the three dimensions of the room exactly. For this, we have to find the Highest Common Factor of 825, 675 and 450.
Prime factorization of 825 = 3×5×5×11
Prime factorization of 675 = 3×3×3×5×5
Prime factorization = 450 = 2×3×3×5×5
Common factors = 3×5×5
H.C.F. = 75
Hence, H.C.F. of 825, 675 and 450 is 75
The length of the longest rod is 75 cm which can measure the three dimensions of the room exactly.
_________________________
HOPE , IT HELPS ... ✌️
Answered by
4
Step-by-step explanation:
Initially,The given values are 825cm, 675cm, 450cm.
Basically we need to find the length{in cm} of rod which is a factor of 825,675 and 450.
By using Prime Factorization:-
825=3x5²x11
675=3²x5²
450=2x3²x5²
From the above factorization,We got H.C.F⇒3x5²=75.
∴The Longest length rod Which measures the 3 dimensions of the room exactly will surely be "75cm Long".
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