Math, asked by gopal361, 1 year ago

the Length breadth and height of a room are 8 metre 25 CM 6 CM 75 cm and 4 m 50 cm respectively find the longest tape which can measure the three dimension of the room when used and exact number of times

Answers

Answered by mhlangatinaishe
0
i guess this is the answer

8,25x6,75x4,50=250.59375
Answered by Anonymous
13

➪ \sf \red{Answer:-}

 \huge{ ➫} \tt GIVEN:-

length \: of \: room \:  = 7m25cm = 725cm \\ breadth \: of \: room \:  = 9m25cm = 925cm \\ height \: of \: room \:  = 8m25cm = 825cm

\huge ➫ \sf FIND:-

now \: we \: find \: HCF \: of \: 725,925 \: and \: 825

{\huge ➫  {\mathfrak{Solution:-}}}

725 = 5 \times 5 \times29

925 = 5 \times 5 \times 37

825 = 3 \times 5 \times 5 \times 11

so, \: heighest \: common \: factor \: is \: 5 \times 5 = 25

therefore \: HCF \: of \: 725,925,825 \: is \: 25.

\therefore 25m is \:  the  \: longest \:  tape \:  measure \:  which  \: can  \: measure \:  all  \: the  \: dimensions.

so, \: answer \: is \:  \boxed{ \mathfrak{ 25m}}

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