Question

The Length, Breadth and Height of a room are 825 cm, 675 cm, 450 cm respectively, Find the longest tape which can measure the three dimensions of the room exactly ​

Answer 1

that is total surface area =2( length×bredth ) +3( bredth×height) +2(height×legth)

by substyting values we can get the answer

hope this answer helpful

Answer 2

$\large{\underline{\rm{\orange{\bf{Given:-}}}}}$

Length of the room = 825 cm

Breadth of the room = 675 cm

Height of the room = 450 cm

$\large{\underline{\rm{\orange{\bf{To \: Find:-}}}}}$

The longest tape which can measure the three dimensions of the room exactly.

$\large{\underline{\rm{\orange{\bf{Analysis:-}}}}}$

Factorize the given dimensions.

Then find the HCF by multiplying the factors here.

$\large{\underline{\rm{\orange{\bf{Solution:-}}}}}$

We know that,

• l = Length
• b = Breadth
• h = Height

Given that,

Length = 825 cm

Breadth = 675 cm

Height = 450 cm

Let us factorize all three given dimensions,

$\longrightarrow \sf 825 = 3 \times 5 \times 5 \times 11$

$\longrightarrow \sf 675=3 \times 3 \times 3 \times 5 \times 5$

$\longrightarrow \sf 450=2 \times 3 \times 3 \times 5 \times 5$

Hence, 3, 5 and 5 are the common prime factors.

Thus, HCF = $\sf 3 \times 5 \times 5= \underline{\underline{75}}$

Therefore, it requires 75 cm longest tape to measure the three dimensions of the room.