The length, breadth and height of a room are 825 cm, 675 cm and 450 cm respectively. Find the length of the longest tape which can measure the three dimensions of the room exactly.
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Answer:
75 cm.
Step-by-step explanation:
The longest tape required to measure the three dimensions of the room = HCF of 825, 675 and 450
Prime factorisations of 825, 675 and 450 are
825 = 3 x 5 x 5 x 11
675 = 3 x 3 x 3 x 5 x 5
450 = 2 x 3 x 3 x 5 x 5
Here, common factors are 3, 5 (two times).
∴ HCF of 825, 675 and 450 = 3 x 5 x 5 = 75
Hence, the required longest tape = 75 cm.
Note:
→ Level Class 6 NCERT Mathematics Ch-3 Playing With Numbers Ex- 3.7 Question No. 3.
Thank You!
I too study in class 6!
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