Question

the length breadth and height of a room are 825 cm and 675 and 450 CM respectively find the longest tape which can be measured the three dimension of the room ​

Answer 1

Answer:

To find the longest tape, we have to find the HCF

of the lengths of the room.

Step-by-step explanation:

HCF of 825, 675 and 450 is 5 .

So, the longest tape which can measure the three dimensions of the room is of 5 cm.

Hope it will be helpful for you.

Answer 2

Answer:

✍️${\huge{\purple{\mathfrak{\underline{\underline{Question}}}}}}$✍️

• The length breadth and height of a room are 825 cm and 675 and 450 CM respectively find the longest tape which can be measured the three dimension of the room

✍️${\huge{\purple{\mathfrak{\underline{\underline{Answer}}}}}}$✍️

✈️${\blue{\underline{Given}}}$✈️

• ${\pink{Length\ of\ the\ room=825cm}}$
• ${\pink{Breadth\ of\ the\ room=675cm}}$
• ${\pink{Height\ of\ the\ room=450cm}}$

✈️${\blue{\underline{To\ find}}}$✈️

• ${\red{Longest\ tape\ to\ measure\ all=????}}$

✈️${\blue{\underline{Solution}}}$✈️

Longest tape to measure all the dimension=H.C.F. of 825,675 and 450

Now, do prime Factorisation of all terms i.e.

825=3×5×5×11

675=3×3×3×5×5

450=2×3×3×5×5

Here, 3,5 and 5 are the common factors.

So,H.C.F.=3×5×5=75..

Hence, measure of longest tape that is needed to measure all three dimension of the room is ${\huge{\red{75cm}}}$