Question

The length, breadth and height of a room are 8m, 5m and 3m respectively. If density of air is 1.29 kg m-3 , find the mass of air in the room. Also express the density in C.G.S unit.

Answer 1

Answer:

Step-by-step explanation:

Vol of room= l*b*h

=8*5*3=120 m^3

Density=1.29 kg/m^3

Mass= vol*density

=120*1.29=154.8 kg

Answer 2

Answer:

The mass is 154.8 kg and density in CGS unit is 1290 gm/(cm)³.

Step-by-step explanation:

As per the data given in the question,

We have,

Dimesions of the room is  8m, 5m and 3m respectively.

So, Voulume will be:

$=l\times b\times h\\=8\times 5\times3\\=120\:m^{2}$

As we know,

$Density=\frac{Mass}{Volume}\\ Mass=Density\times Volume\\Mass= 120\times 1.29\\Mass= 154.8\: kg$

Also, we know that CGS unit of volume is gm/(cm)³. So, volume in CGS unit will be = $1.29\:kg/m^{3}\times1000= 1290gm/cm^{3}$.

Hence, The mass is 154.8 kg and density in CGS unit is 1290 gm/(cm)³.

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