Question

the length breadth and height of a room are 9m,14m and 15m respectively find the cost of white washing the four wall of the room at the rate of ruppes 12 per meter square​

Answer 1

$\sf{\underline{Given}}$

• Length of the room = 9 m
• Breadth of the room = 14 m
• Height of the room = 15 m

$\sf{\underline{To\:Find}}$

The cost of white-washing the four walls at the rate of Rs.12 per m²

$\sf{\underline{Solution}}$11

Length of the room = 9 m

Breadth of the room = 14 m

Height of the room = 15 m

$\sf{Area\:of\:four\:walls = 2(Length+Breadth)\times Height\:\:sq.units}$

= $\sf{Area = 2(9+14)\times 15\:\:m^2}$

= $\sf{Area = 2\times23\times15\:\:m^2}$

= $\sf{Area = 690\:\:m^2}$

Now,

Cost of painting 1 m² = Rs.12

$\sf{Cost\:of\:white-washing\:690\:m^2 = 12\times690}$

= $\sf{Cost\:of\:white-washing\:690\:m^2 = 8280}$

Therefore cost of white-washing the four walls of the room is Rs.8280.

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$\sf{\underline{More\:Information}}$

• $\sf{Volume\:of\:a\:cuboid = (Length\times Breadth\times Height)\:cubic\:units}$

• $\sf{TSA\:of\:a\:cuboid = 2(LB + BH + HL)\:sq.units}$

• $\sf{LSA\:of\:cuboid = 2(L+B)\times H\:\:units}$

$\sf{\underline{Note}}$

L = Length

B = Breadth

H = Height

LSA = Lateral surface area (also known as Area of four walls)

TSA = Total Surface Area.

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