Question

the length breadth and height of a room are 9m 5.6m and 3.5 m respectively .find the no. of tiles required to cover the floor of room if each tile is 90cm by 50 cm

Answer 1

Given:

length = 9m
Breadth = 5.6m
Height = 3.5m

Area of floor = l × b
= 9 × 5.6
= 50.4 m^2

Area of a Tile = l × b = 0.9 × 0.5 = 0.45 m^2

Therefore Tiles needed = Area of Floor/area of a Tile
= 50.4/0.45
=112.

Answer 2

Solutions :-

Given :
The length, breadth and height of a room are 9m, 5.6 m and 3.5 m respectively
So,
Length = 9 m = 900 cm
Breadth = 5.6 m = 560 cm

Size of each tiles = 90 cm by 50 cm

Find the number of tiles required :-

$\bold{no. \: \: of \: \: tiles \: \: required} \: = \frac{\bold{area \: \: of \: \: floor}}{\bold{area \: \: of \: \: tiles}} \\ \\ = \frac{\bold{900 \times 560}}{\bold{90 \times 50}} \\ \\ = \frac{\bold{504000}}{\bold{4500}} = \bold{112}$

Hence,
112 tiles are required to cover the floor of the room.