Question

the length, breadth and height of a room are in ratio of 2:2:1 . the lateral surface of the room is 972 m².​

Answer 1

Answer:

Hey user.

Let the angle be 5x,4x nd 2x.

TSA=2(lb+bh +hl=1216

2(20x²+8x+10x)=1216

76x-1216

x2-1216/76

x2-16

x=4cm.

Dimensions are 20cm, 16cm nd 8cm.

Volume=lbh

=>20*16*8

=2560cm

Answer 2

Answer:

let common ratio between sides x

L=2x, b=2x, h=1x

lateral Surface area= 2(l+b)h

972= 2(2x+2x)1x

972= 2 × 4x^2

972/2= 4x^2

486/4= x^2

11.02= x

L= 2×11.02=22.04m

b= 2×11.02=22.04m

h= 1×11.02= 11.02m