Math, asked by manishgg0987, 1 day ago

The length, breadth and height of a room in the shape of a cuboid are increased by 10%, 20% and 50% respectively. Find the percentage change in the volume of the cuboid.

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Answered by vivek7018395906
0

shravan is the month of rain _____ three questions 6th class unseen passage

Answered by Anonymous
3

\large\mathfrak\pink{Solution} \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \\  \\  \\  \mathtt{Given:\:The\: length,\:breadth\:and \: height \: of \: a} \\  \mathtt{room \: increased \: by \: 10\% \: 20\% \: and \: 50\% \: respectively.} \\  \\ \mathtt{Formula\: used:\: Volume\:of\: cuboid\: length×breadth×height} \\  \\ \mathtt{Calculation:} \\ \mathtt{Let\:the\: length,\: breadth\:and\:height}  \\ \mathtt{be\:l,b \: and\:h\: respectively} \\  \\ \mathtt{Now\:new\: dimensions\:after\: increment} \\  \mathtt{New \: lenght = l + 10\% \: of \: l = 1.1l} \\  \mathtt{New \: breadth \:  = b + 20\% \: of \: b = 1.2b} \\  \mathtt{New \: height = h + 50\% \: of \: h = 1.5h} \\  \\  \mathtt{Original \: volume  = l \times b \times h \:  \implies \: lbh} \\ \mathtt{New\: volume=(1.1)l×(1.2)b×(1.5)h\: \implies\:1.98lbh} \\ \mathtt{Percent\: increase\:in\: volume=(1.98lbh)/(lbh)×100\implies\:98}  \\  \\   \large\mathtt {\fbox{ans = 98}}

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