Question

the length, breadth ,and height of a room is 10m,8m,and 2.5m long find total surface area of room and also find cost points of its four side walls and ceiling at a rate of rs 15 per m²​

Answer 1

GivEn:-

• The length, breadth and height of a room is 10 m, 8 m, 2.5 m respectively.
• The cost of painting is at a rate of Rs. 15/m².

To Find:-

• The total surface area of room
• The cost of painting four side walls and ceiling.

Solution:-

The formula of total area of four walls of a room,

$\boxed{ \pink{ \sf{A = 2h(l + b)}}}$

• A = Total surface area of four walls
• h = height of the room
• l = length of the room
• b = breadth of the room

Now, putting the values in the formula we get,

$\implies \sf \: A = 2 \times 2.5(10 + 8)$

$\implies \sf \: A = 5 \times 18$

$\implies \sf \: A = 90$

To find the area of ceiling, we will use the following formula :

$\boxed{ \pink{ \sf{A= l \times b}}}$

Now, putting the values,

$\implies \sf \: A = 10 \times 8$

$\implies \sf \: A = 80$

Total area of the four walls and the ceiling of the room is = ( 90 + 80 ) = 170 m²

▪ It requires Rs. 15/m² for painting,

Therefore, the total cost required

$\implies \sf \: 170 \times 15$

$\implies \sf \: 2550$