The length, breadth ,and height of a room is 10m,8m,and 2.5m long find total surface area of room and also find cost points of its four side walls and ceiling at a rate of rs 15 per m².
Answers
Step-by-step explanation:
It is given that length, breadth and height of a room are 8 m, 5 m and 3 m respectively.
Area of four walls of the room is: 2h(l+b)
A=2h(l+b)=2×3(8+5)=6×13=78 m
2
Area of the ceiling is:
A=l×b=8×5=40 m
2
Total area of the four walls and the ceiling of the room is 78+40=118 m
2
It is given that cost of white washing is Rs.15/m
2
, therefore,
Total cost of white washing is:
118×15=1770
Hence, the cost of white washing the walls is Rs.1770.
Answer:
Answer:
Given:-
The length, breadth and height of a room is 10 m, 8 m, 2.5 m respectively.
The cost of painting is at a rate of Rs. 15/m².
To Find:-
The total surface area of room
The cost of painting four side walls and ceiling.
Solution:-
The formula of total area of four walls of a room,
A = 2h ( l + b )
A = Total surface area of four walls
h = height of the room
l = length of the room
b = breadth of the room
Now, putting the values in the formula we get,
A = 2 × 2.5 ( 10 + 8 )
A = 5 × 18
A = 90
To find the area of ceiling, we will use the following formula :
Area = Length × Breadth
Now, putting the values,
A = 10 × 8
A = 80
Total area of the four walls and the ceiling of the room is = ( 90 + 80 ) = 170 m²
▪ It requires Rs. 15/m² for painting,
Therefore, the total cost required = 170 × 15
= 2550