Question

The length, breadth ,and height of a room is 10m,8m,and 2.5m long find total surface area of room and also find cost points of its four side walls and ceiling at a rate of rs 15 per m².​

Answer 1

Step-by-step explanation:

It is given that length, breadth and height of a room are 8 m, 5 m and 3 m respectively.

Area of four walls of the room is: 2h(l+b)

A=2h(l+b)=2×3(8+5)=6×13=78 m

2

Area of the ceiling is:

A=l×b=8×5=40 m

2

Total area of the four walls and the ceiling of the room is 78+40=118 m

2

It is given that cost of white washing is Rs.15/m

2

, therefore,

Total cost of white washing is:

118×15=1770

Hence, the cost of white washing the walls is Rs.1770.

Answer 2

GIVEN:-

• The Length, breadth and height of a room is 10m, 8m, 2.5m respectively.
• The cost of painting is at a rate of Rs.15/m².

TO FIND:-

• The total surface area of room
• The cost of painting four side walls and ceiling.

SOLUTION:-

The formula of total area of four walls of a room,

${\boxed{ \red {\tt{A = 2h(l + b)}}}}$

• A = Total surface area of four walls
• h = Height of the room
• l = Length of the room
• b = breadth of the room

Now, putting the values in the formula we will use the following formula :-

${\boxed {\pink{ \tt{A = l \times b}}}}$

Now putting the values,

$\implies \tt{a = 10 \times 8}$

$\implies \tt{a = 80}$

Total area of the 4 walls and the ceiling of the room is = (90+80) = 170m².

•It requires Rs 15/m² for painting.

$\therefore$

Therefore the total cost required.

$\implies \tt{170 \times 15}$

$\implies \tt{2550}$