Math, asked by rakdogra1, 10 months ago

The length, breadth and height of a school auditorium are 20 m, 15 m and 10 m respectively. Find the cost of painting the four walls at the rate of Rs 750 per m².​

Answers

Answered by ItsMysteriousGirl
10

\huge\bf\underline{\underline{Given:}}

Length of auditorium = 20m

Breadth of auditorium = 15m

Height of auditorium = 10m

Rate of painting walls = \sf{Rs.750/m^2}

\huge\bf\underline{\underline{To\: find:}}

Cost of painting the four walls

\huge\bf\underline{\underline{Solution:}}

We need to paint the four walls of the auditorium.Hence, we need to find the lateral surface area of the auditorium.

Lateral Surface Area of Auditorium

= 2h(l+b)

= 2(10)(20 + 15)

= 20(35)

= \sf{700m^2}

Cost of painting four walls

= Rate × Area

= 750 × 700

= Rs.525000

Therefore, the cost of painting four walls of the auditorium is Rs.525000 only.

___________________________

@ItsMysteriousGirl

Answered by avni1433
4

Answer:

the answer is 525000

Step-by-step explanation:

2h (l+b)

2(10)(20+15)

20(35)= 20 ×35 = 700 m cube

cost =Rate × area

= 750 ×700

=525000

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