the length ,breadth and height of cuboidal tank are 150cm, 120cm and 110cm respectively. the tank has 129600cm3 of water in it. 100 porous bricks each having dimensions 20cm X 10cm X 10cm and arwe placed in the tank. calculate the raise in the water level of the tank. if each bricks absorbs 1/10 of its own volume
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Data regarding volume of water in the tank = 129,600 cm^3 or 1,296,000 cm³ ??
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Volume of the tank = 150 * 120 * 110 cm³ = 1, 980, 000 cm³
base area of the tank = 150 * 120 = 18, 000 cm²
volume of water in the tank = 129, 600 cm³
filled height of water in the tank = 129, 600 / 18 000 = 7. 2 cm
Volume of the porous bricks = 20 * 10 * 10 = 2, 000 cm³ each
Amount of water absorbed by each brick = 1/10 * 2, 000 = 200 cm³
Amount of water absorbed by all 100 bricks = 20, 000 cm³
Volume of water remaining = 129, 600 - 20, 000 cm³ = 109, 600 cm³
Now volume occupied by the bricks = 100 * 2, 000 = 200, 000 cm³
Total volume of bricks + water = 309, 600 cm³
Height of water in the tank now = total volume / base area
= 309, 600 / 18, 000 = 17.2 cm
Rise in the level of water = 17.2 - 7.2 = 10 cm
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Volume of the tank = 150 * 120 * 110 cm³ = 1, 980, 000 cm³
base area of the tank = 150 * 120 = 18, 000 cm²
volume of water in the tank = 129, 600 cm³
filled height of water in the tank = 129, 600 / 18 000 = 7. 2 cm
Volume of the porous bricks = 20 * 10 * 10 = 2, 000 cm³ each
Amount of water absorbed by each brick = 1/10 * 2, 000 = 200 cm³
Amount of water absorbed by all 100 bricks = 20, 000 cm³
Volume of water remaining = 129, 600 - 20, 000 cm³ = 109, 600 cm³
Now volume occupied by the bricks = 100 * 2, 000 = 200, 000 cm³
Total volume of bricks + water = 309, 600 cm³
Height of water in the tank now = total volume / base area
= 309, 600 / 18, 000 = 17.2 cm
Rise in the level of water = 17.2 - 7.2 = 10 cm
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