The length breadth and height of cuboidal tank are in ratio 3 2 1 if vol of bore is 48cm3 find sa
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l:b:h = 3:2:1
volume = 48
(3x)*(2x)*(x) = 48
x=2
l=6; b=4; h=2
Total surface area=2*(lb+bh+lh)=88sq.cm
volume = 48
(3x)*(2x)*(x) = 48
x=2
l=6; b=4; h=2
Total surface area=2*(lb+bh+lh)=88sq.cm
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