Question

the length breadth and height of metalic parallelopiped is 16 cm , 11 cm and 10 cm respectively . it was melted and cast into discs . the diameter and thickness of each discs was 4 cm and 0.2 cm respectively what was the number of discs formed? (pie 22/7 complete the following activity and find the answer​

Answer 1

Answer:

volume=16×11×10=1760cm^3

volume of each disc=22/7R^2H

=22/7×2×2×0.2

=17.6/7cm^3

no of discs can be formed=1760/17.6/7

=1760×7/17.6=7×100

=700

Answer 2

The number of discs formed = 701

Explanation:

Given : The length  , breadth and height of metalic parallelopiped is 16 cm , 11 cm and 10 cm respectively .

Volume of metalic parallelopiped =  length x breadth x height

16 x 11 x10 = 1760  cubic cm.

For disc,

Diameter = 4 cm

i.e. radius : r= 2 cm  [half of diameter]

Thickness = h= 0.2 cm

Volume of disc : $\pi r^2h$  

$=\dfrac{22}{7}(2)^2(0.2)\approx2.51$  cubic cm.

Now , the number of discs formed = (Volume of metalic parallelopiped) ÷ (Volume of disc)

1760 ÷ 2.51 ≈701

Hence, the number of discs formed = 701.

# Learn more :

Find the ratio of volume of cylinder. When the radius is halved, and the height is same to that of volume of cylinder.​

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