Question

the length breadth and height of two cuboids are 30cm,25,15 and 35cm,20 and 12cm. compare their surface area. which will have more volume​

Answer 1

Fisrt Cuboid :-

Given :

• Length of cuboid = 30 cm
• Breadth of cuboid = 25 cm
• Height of cuboid = 15 cm

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To Find :

• Total surface area of the cuboid

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Solution :

★ T.S.A of cuboid = 2 ( LB + BH + HL )

→ T.S.A = 2 ( 30×25 + 25×15 + 15×30 )

→ T.S.A = 2 ( 750 + 375 + 450 )

→ T.S.A = 2 × 1575

→ T.S.A = 3150 cm²

★ Volume of cuboid = L × B × H

→ Volume = 30 × 25 × 15

→ Volume = 11250 cm³

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SECOND Cuboid :-

Given :

• Length of cuboid = 35 cm
• Breadth of cuboid = 20 cm
• Height of cuboid = 12 cm

_____________________________

To Find :

• Total surface area of the cuboid

_____________________________

Solution :

★ T.S.A of cuboid = 2 ( LB + BH + HL )

→ T.S.A = 2 ( 35×20 + 20×12 + 12×35 )

→ T.S.A = 2 ( 700 + 240 + 420 )

→ T.S.A = 2 × 1360

→ T.S.A = 2720 cm²

★ Volume of cuboid = L × B × H

→ Volume = 35 × 20 × 12

→ Volume = 8400 cm³

∴ First Cuboid have more Area and Volume

Answer 2

Here it is given that, we have to find the surface area and also from the two cuboids also compare that which one has more volume.

For the First Cuboid:-

Given :

Length $= 30$ cm

Breadth $= 25$ cm

Height $= 15$ cm

As we know that,

Total Surface Area of cuboid $= 2 ( LB + BH + HL )$

 $=>2 ( 30\times25 + 25\times15 + 15\times30 )$

$= >2 ( 750 + 375 + 450 )$

$=> 2 \times 1575$

$=> 3150$ cm²

Now for, the volume we have the formula:

The volume of cuboid = $L \times B \times H$

$=> 30 \times25 \times15$  

$= >11250$ cm³

For the Second Cuboid:-

Given :

Length$= 35$ cm

Breadth $= 20$ cm

Height $= 12$ cm

 As we know that,

Total Surface Area of cuboid $= 2 ( LB + BH + HL )$

$=> 2 ( 35\times20 + 20\times12 + 12\times35 )$

$=> 2 ( 700 + 240 + 420 )$

$= >2720$ cm²

Now for, the volume we have the formula:

The volume of cuboid = $L \times B \times H$

$=> 35 \times 20 \times 12$

$= >8400$ cm³

Hence, First Cuboid has more surface area and Volume.