Question

the length , breadth and heigth of a rectangular block of wood wre measured to be : l=12.13+- 0.02 cm , b= 8.16 +- .01 cm, h = 3.46 +-0.01 cm Determine the percentage error in the volume of the block .

Answer 1

Answer:

Hey Buddy here's ur answer

0.58 %

Volume = 342.47 + 1.98

Explanation:

The length, breadth and height of a rectangular block of wood were measured to be,

1= 12.1324 0.02 cm, b=8.16 +0.01cm, h = 3.46+0.01 cm.

Determine the percentage error in the volume

of the block.

Length = 12.13 +0.02 cm = L + ΔL

Breadth = 8.16 +0.01 cm = B + ΔB

Height = 3.46 + 0.01 cm = H + ΔH

Volume = Length * Bredth * Height = V + ΔV

V = LBH = 12.13 * 8.16 * 3.46 = 342.47

ΔV/V = ΔL/L + ΔB/B + ΔH/H

=> ΔV/342.47 = 0.02/12.13 + 0.01/8.16 + 0.01/3.46

=> ΔV = 0.57 + 0.42 + 0.99

=> ΔV = 1.98

Volume = 342.47 + 1.98

% error = (1.98/342.47) * 100 = 0.58 %

Answer 2

Pls see the attachment