the length breadth and hight of a room 5m 60cm ,3m 50cm and 2m 10cm respectively find the length of greatest rod that can measure the room exactly
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Length of the room = 8.25 m or 825 cm
Breadth of the room = 6.75 m = 675 cm
Height of the room = 4.50 m = 450 cm
We have to find the longest rod that can measure the three dimensions of the room exactly. For this, we have to find the Highest Common Factor of 825, 675 and 450.
Prime factorization of 825 = 3*5*5*11
Prime factorization of 675 = 3*3*3*5*5
Prime factorization = 450 = 2*3*3*5*5
Common factors = 3*5*5
H.C.F. = 75
Hence, H.C.F. of 825, 675 and 450 is 75
The length of the longest rod is 75 cm which can measure the three dimensions of the room exactly.
Breadth of the room = 6.75 m = 675 cm
Height of the room = 4.50 m = 450 cm
We have to find the longest rod that can measure the three dimensions of the room exactly. For this, we have to find the Highest Common Factor of 825, 675 and 450.
Prime factorization of 825 = 3*5*5*11
Prime factorization of 675 = 3*3*3*5*5
Prime factorization = 450 = 2*3*3*5*5
Common factors = 3*5*5
H.C.F. = 75
Hence, H.C.F. of 825, 675 and 450 is 75
The length of the longest rod is 75 cm which can measure the three dimensions of the room exactly.
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