The length, breadth and thickness of a block are given by l=12 cm, b=6 cm and t=2.45 cm. The volume of the block according to the idea of significant figure should be
(a) 1 × 10² cm³
(b) 2 × 10² cm³
(c) 1.763 × 10² cm³
(d) 1.76 × 10² cm³
class 11 , chapter 2 - units and measurements
Answers
Answered by
83
Hi ,
Dimensions of the block ,
Length ( l ) = 12 cm
Breadth ( b ) = 6 cm
Height ( h ) = 2.45 cm
volume of the block = lbh
V = 12 × 6 × 2.45
V = 176.4 cm³
V = 176.4 × ( 10²/10² ) cm³
V = 1.764 × 10² cm³
V = 2 × 10² cm³
Option ( b ) is correct.
I hope this helps you.
: )
Dimensions of the block ,
Length ( l ) = 12 cm
Breadth ( b ) = 6 cm
Height ( h ) = 2.45 cm
volume of the block = lbh
V = 12 × 6 × 2.45
V = 176.4 cm³
V = 176.4 × ( 10²/10² ) cm³
V = 1.764 × 10² cm³
V = 2 × 10² cm³
Option ( b ) is correct.
I hope this helps you.
: )
Anonymous:
sir , no: of significant figures in the ans must be 1
Answered by
42
= > Given length of a block = 12cm.
= > Given Breadth of a block = 6cm.
= > Given thickness of a block = 2.45cm.
We know that Volume of a block = length * breadth * thickness
= 12 * 6 * 2.45
= 176.4
= 1.764 * 10^2 cm^3.
The minimum number of significant figures is 1. Therefore the volume will contain only one significant figure.
Hence volume V = 2 * 10^2 cm^3.
Hope this helps!
= > Given Breadth of a block = 6cm.
= > Given thickness of a block = 2.45cm.
We know that Volume of a block = length * breadth * thickness
= 12 * 6 * 2.45
= 176.4
= 1.764 * 10^2 cm^3.
The minimum number of significant figures is 1. Therefore the volume will contain only one significant figure.
Hence volume V = 2 * 10^2 cm^3.
Hope this helps!
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