Question

The length, breadth and thickness of a rectangular sheet of metal are 4.234m, 1.005m and 2.01cm respectively. Give area and volume of a sheet upto correct significant figures.

Answer 1

Answer:

0.086 m^3

Step-by-step-solution:

Given

Length = 4.234m

Breadth = 1.005m

Thickness = 2.01cm = 2.01/100 = .0201m

.•. 1m = 100cm

We know ,

${ \sf {\boxed {\sf{volume = length \times breadth \times height(here \: thickness)}}}}$

$\sf \implies \: volume = \: 4.234m \times 1.15m \times .0201m$

$\sf \implies \: volume = 0.086 {m}^{3}$

What you need to know ?

• Volume of cuboid = Length × Breadth × height.

• Volume of cube = side^3

• Volume of cone = π r^2 h/3

• Volume of cylinder = π r^2 h

• Volume of sphere = 4/3 π r^3

Answer 2

Given:-

Length = 4.234 m

Breadth = 1.005 m

Height (thickness of sheet) = 2.01 cm = 0.0201 m

Solution:-

$Area \: = \: 2(lb \: + \: bh \: + hl) \\ = 2(4.234 \: \times1.005 \: + 1.005 \: \times 0.201 \: + \: 0.201\: \times \: 4.234) \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \: 2(4.25517 + 0.0202005 + 0.08551034) \\ = (8.7209478) \\= 8.72 \: {m}^{2}$

Now,

$Volume \: = \: l \: \times \: b \: \times \: h \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 4.234 \: \times 1.005 \: \times \: 0.0201 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 0.0855 \: m ^{3}$

$Hence \: The \: area \: is \: 8.72 \: m ^{2} \: \: and \: \\ Volume \: is \: 0.0855 {m}^{3}$