Question

the length, breadth and thickness of a rectangular sheet of metal are 4•234 m ,1•005 m, and 2•01 cm respectively give the area and volume of the sheet to correct significant figures


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Answer 1

$\large\rm { A = 2(L × B + B × T + T × L)}$

$\large\rm { \therefore A = 2(4.234 × 1.005 + 1.005 × 0.0201 + 0.0201 × 4.234)}$

$\large\rm { A = 8.721 m² }$ to correct significant digits

$\large\rm { V = LBT}$

$\large\rm { V = 4.234 × 1.005 × 0.0201}$

$\large\rm { V = 0.0855 m³}$ to correct significant digits

Answer 2

Answer:

\large\rm { A = 2(L × B + B × T + T × L)}A=2(L×B+B×T+T×L)

\large\rm { \therefore A = 2(4.234 × 1.005 + 1.005 × 0.0201 + 0.0201 × 4.234)}∴A=2(4.234×1.005+1.005×0.0201+0.0201×4.234)

\large\rm { A = 8.721 m² }A=8.721m² to correct significant digits

\large\rm { V = LBT}V=LBT

\large\rm { V = 4.234 × 1.005 × 0.0201}V=4.234×1.005×0.0201

\large\rm { V = 0.0855 m³}V=0.0855m³ to correct significant digits