Question

The length, breadth and thickness of a rectangular sheet of metal are 3.234 m, 2.005 m, and 1.01 cm respectively. Give the area and volume of the sheet to correct significant figures​

Answer 1

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Answer 2

Given: The length of the rectangular sheet$=3.234m,$

The breadth of the rectangular sheet$=2.005m,$

The thickness of the rectangular sheet$=1.01cm.$

We have to find the area and volume of the rectangular sheet.

For this, we are using the formula,

$\mathrm{A}=2 \times(\mathrm{L} \times \mathrm{B}+\mathrm{B} \times \mathrm{T}+\mathrm{T} \times \mathrm{L}),\\\mathrm{V}=\mathrm{L} \times \mathrm{B} \times \mathrm{T}$

We have, $L=3.234m, B=2.005 m, T=1.01 cm.$

Now,

$=>\mathrm{A}=2 \times(\mathrm{L} \times \mathrm{B}+\mathrm{B} \times \mathrm{T}+\mathrm{T} \times \mathrm{L})\\=>A=2\times((3.234\times2.005)+(2.005\times0.0101)+(0.0101\times3.234))\\=>A=2\times(6.4841+0.0202+0.0326)\\=>A=2\times(6.5369)\\=>A=13.07m^{2}$

And

$=>\mathrm{V}=\mathrm{L} \times \mathrm{B} \times \mathrm{T}\\=>V=3.234\times2.005\times0.0101\\=>V=0.0654m^{3}$

Hence, the area and volume of the sheet are $13.07m^{2} and 0.06549m^{3}$to the correct significant digits.