The length, height and volume of a box is 10 m, 7 m and 175 cubic m respectively. Find its breadth. 32. (a) Convert 47 rupees 70 paise into paise. (b) Convert 25.4 cm into cm-mm. 33. The weight of one chocolate is 80 g. By how many such chocolates can you make a box weighing 2kg? 34. A rectangular field has an area of 1,80,000 square m and breadth of the field is 400 m. Find the length of the field. 35. Sunil counted the vehicles passed by a road during an hour and prepared the following chart. (a) How many vehicles in total did Sunil see? (b) The number of vehicles which is more than 15? 36. Divide 3511.06 by 35.
Answers
Answer:
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Step-by-step explanation:
31)
The length of a cuboidal box (l) = 10 m
Let the breadth of the cuboidal box be b
The height of the cuboidal box (h) = 7m
We know that
The volume of a cuboid = lbh cubic units
=> 10×b×7
=> 70 b cubic metres
According to the given problem
The volume of the given box = 175 m³
=> 70 b = 175
=> b = 175/70
=> b = 35/14
=> b = 2.5 m
The breadth of the box. = 2.5 m
32)
a)
Given that
47 rupees and 70 paise
We know that
1 rupee = 100 paise
47 rupees = 47×100 paise
=> 47 rupees = 4700 paise
Now,
47 rupees and 70 paise
=> 4700+70
=> 4770 paise
b)
Given that
25.4 cm
We know that
1 cm = 10mm
=> 25.4 cm = 25.4×10 mm
=> 254 mm
33)
The weight of one chocolate = 80 g
Total weight of the box = 2kg
We know that
1 kg = 1000g
=> 2 kg = 2000g
The number of chocolates
= Total weight of the box / Weight of each chocolate
= 2000/80
= 200/8
= 25
The number of chocolates required = 25
34)
Let the length of the field be X m
Breadth of the field = 400 m
Area of a rectangle = lb sq.units
=> 400×X = 400X sq.m
According to the given problem
A rectangular field has an area of 1,80,000
=> 400X = 180000
=> X = 180000/400
=> X = 1800/4
=> X = 450
The length of the field = 450 m
35)
There is no chart given
36)
Given number = 3511.06
Given divisor 35
35) 3511.06(100.316
35
_______
0 110
105
________
56
35
_________
210
210
___________
0
____________
Answer = 100.316