Math, asked by akshay497531, 3 months ago

The length od hypotenuse of an isosceles right triangle is 10cm, find its base and height? what is the area of this triangle​

Answers

Answered by Sandradutta05
0

Answer:

25 sq cm

Step-by-step explanation:

From Pythagoras: h*h = a*a+b*b

As the triangle is isosceles, the non-hypotenuse sides have the same length.

So: h*h = 2*a*a

=> a = root(h*h/2)

The area of the triangle is base * height / 2

So: area = a*a/2

=> root(h*h/2)*root(h*h/2)/2

=> h*h/4

=> 10 * 10 / 4

=> 25 square cm

Hope this is helpful to you : )

Answered by nousheenshameer2005
0

Answer:

x²+x²=10²

2x²=100

x²= 50

x= 5 root 2

s= 1/2x²

s= 1/2 × 50

s= 25

Similar questions