Question

The length of a basketball court is ((6x^2 + 20x)m) . If the length is 2x times the width, what is the dimension of the court?

Answer 1

$\huge\mathcal \colorbox {gold}{{Given → }}$

• The length of a basketball court is (6x² + 20x) m.
• The length is 2x times the width.

$\huge \mathcal \colorbox{lightpink}{{Solution →}}$

Let the width be z m.

Length = (6x² + 20x) m.

Length is 2x times width.

$\sf \colorbox{lightblue}{{According to condition,}}$

$2x(z) = (6x^{2} + 20x)$

$➠z = \frac{(6 {x}^{2} + 20x) }{2x}$

$➠z = (3x + 10)$

$\huge \mathcal \colorbox {lightgreen}{{Hence →}}$

$z = (3x + 10)$

$Width = z \: m = (3x + 10)m$

Therefore →

The width of the court is (3x + 10) m.

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