Math, asked by munna6130, 4 months ago

The length of a basketball court is (6x2 +
20x) m. If the length is 2x times the width,
what is the width of the court?

Answers

Answered by jeevankumarpanigrahi
1

Answer:

32 m

Step-by-step explanation:

6× 2 + 20 m

= 12 + 20 m

= 32 m

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Answered by Anonymous
6

\huge\bold{\mathtt{Question⇒}}

The length of a basketball court is (6x²+ 20x) m. If the length is 2x times the width, what is the width of the court?

\huge\bold{\mathtt{Given⇒}}

  • The length of a basketball court is (6x² + 20x) m.

  • The length is 2x times the width.

\huge\bold{\mathtt{To\:find⇒}}

The width.

\huge\bold{\mathtt{Solution⇒}}

Let the width be y m.

Length = (6x² + 20x) m.

Length is 2x times width.

According to condition,

2x(y) = (6x² + 20x)

➳\:y = {\frac{(6x²+20x)}{2x}}

➳\:y = (3x+10)

\huge\bold{\mathtt{Hence⇒}}

y = (3x + 10)

Width = y m = (3x + 10) m

\huge\bold{\mathtt{Therefore⇒}}

The width of the court is (3x + 10) m.

\huge\bold{\mathtt{Done}}

  • \large\bold{\mathtt{Hope\:this\:helps\:you.}}

  • \large\bold{\mathtt{Enjoy\: learning\:!!}}

  • \large\bold{\mathtt{Have\:a\:nice\:day.}}
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