The length of a chain used as the boundary of a semicircular park 90m.find the area of the park
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Solution:-
Length of the boundary of the semicircular park = 90 m
⇒ πr + 2r = 90
⇒ r(22/7 + 2) = 90
⇒ r = (90*7)/36
⇒ r = 17.5 m
Area of the semicircular park = 1/2πr²
= 1/2*22/7*17.5*17.5
= 481.25 sq m
Answer.
Length of the boundary of the semicircular park = 90 m
⇒ πr + 2r = 90
⇒ r(22/7 + 2) = 90
⇒ r = (90*7)/36
⇒ r = 17.5 m
Area of the semicircular park = 1/2πr²
= 1/2*22/7*17.5*17.5
= 481.25 sq m
Answer.
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this is the right answer
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