The length of a chord 8 cm is away from the radius of the circle.The radius of the circle is 30 cm find the diameter of the circle
Answers
Step-by-step explanation:
Consider AB as as the chord of the circle with O as the centre Construct OL ⊥ AB From the figure we know that OL is the distance from the centre of chord It is given that AB = 30cm and OL = 8cm Perpendicular from the centre of a circle to a chord bisects the chord So we get AL = ½ × AB By substituting the values AL = ½ × 30 By division AL = 15cm Consider △ OLA Using the Pythagoras theorem it can be written as OA2 = OL2 + AL2 By substituting the values we get OA2 = 82 + 152 On further calculation OA2 = 64 + 225 By addition OA2 = 289 By taking the square root OA = √289 So we get OA = 17cm Therefore, the radius of the circle is 17cm.Read more on Sarthaks.com - https://www.sarthaks.com/727424/chord-length-30cm-drawn-distance-8cm-from-the-centre-circle-find-out-the-radius-the-circle