Question

the length of a chord of a circle is 20 and the distance from the center is 24 find the diameter of the circle

Answer 1

$\huge \bf{ \red{answer}}$

$\bf{62.48 \: units}$
$\bf{question - }$
the length of a chord of a circle is 20 and the distance from the center is 24 find the diameter of the circle

$\bf{step \: by \: step \: explanation}$

Given -

length of chord= 20 units

and distance from the center=24 units


hence in figure u can see a right angled triangle.

so use Pythagoras theorem


OA^2=OC^2+AC^2

OA^2=(20)^2+(24)^2

OA^2=400+576

OA^2=976

OA=_/976

OA= 31.24 units

hence diameter= 31.24+31.24

=> 62.48 units

$\bf{thanks}$
.

Answer 2

_______Heyy Buddy ❤_______

_____Here's your Answer ________

Given :-


Length of Chord = 20

Distance b/w chord and Centre = 24.

To Find :-

Diameter = ?

Find :-

We know that, the line passing through the centre to the chord perpendicularly bisect the chord.

=> By Pythagoras theorem,


$= > {ab}^{2} = {bo}^{2} + {ao}^{2} \\ \\ = > {ab}^{2} = {20}^{2} + {24}^{2} \\ \\ = > {ab}^{2} = 400 + 576 \\ \\ = > {ab}^{2} = 976 \\ \\ = > ab = \sqrt{976} \\ \\ = > ab = 31.24$

So,

Radius = 31.24

=> Diameter = 2 × radius

=> Diameter = 2 × 31.24

=> Diameter = 62.48
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