The length of a chord PQ of a circle with its centre O is 4cm and the distance of PQ from the point O is 2.1 cm. Let us write by calculating, the length of its diameter.
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Answered by
5
Answer:
Given PQ = 4cm, Distance from the Center is 2,1cm
PQ = 2 PD
Perpendicular from the center of the circle to any Chord bisects it in two line segments
Step-by-step explanation:
PD
⇒ PD = 2cm
In O PD , Using Pythagoras Theorem
⇒ OD2 + PD 2 = OP2
⇒ OP2 = 2.12 + 22
⇒ OP2 = 8.41
⇒ OP = 2.9cm
Answered by
1
Answer:
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