The length of a chord which is at a distance of 5 cm from the centre of a circle whose radius is 10 cm is :
5√3 cm
10√3 cm
2.5√3 cm
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Step-by-step explanation:
Let AB be a chord of a circle with centre O and radius 13 cm. Draw OL⊥AB. Join OA.
Here, OL=5 cm,OA=13 cm.
In right triangle OLA,
OA
2
=OL
2
+AL
2
13
2
=5
2
+AL
2
AL
2
=144
AL=12
Since the perpendicular from the centre to a chord bisects the chord. Therefore,
AB=2AL=2×12=24 cm
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