The length of a conductor wire with a length of 2 l and transverse A is 8 ohms. Find the length of another conductor wire of the same length l / 2 and when its transverse 2A.
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2
Explanation:
•⇒ Length (l) is doubled & Area of cross section (A) is halved.
⇒ Length (l) is doubled & Area of cross section (A) is halved.l becomes 2l & A becomes
⇒ Length (l) is doubled & Area of cross section (A) is halved.l becomes 2l & A becomes 2
⇒ Length (l) is doubled & Area of cross section (A) is halved.l becomes 2l & A becomes 2A
⇒ Length (l) is doubled & Area of cross section (A) is halved.l becomes 2l & A becomes 2A
⇒ Length (l) is doubled & Area of cross section (A) is halved.l becomes 2l & A becomes 2A
⇒ Length (l) is doubled & Area of cross section (A) is halved.l becomes 2l & A becomes 2A R=P
⇒ Length (l) is doubled & Area of cross section (A) is halved.l becomes 2l & A becomes 2A R=P A
⇒ Length (l) is doubled & Area of cross section (A) is halved.l becomes 2l & A becomes 2A R=P AL
⇒ Length (l) is doubled & Area of cross section (A) is halved.l becomes 2l & A becomes 2A R=P AL
⇒ Length (l) is doubled & Area of cross section (A) is halved.l becomes 2l & A becomes 2A R=P AL
⇒ Length (l) is doubled & Area of cross section (A) is halved.l becomes 2l & A becomes 2A R=P AL now take l=2l,A=
⇒ Length (l) is doubled & Area of cross section (A) is halved.l becomes 2l & A becomes 2A R=P AL now take l=2l,A= 2
⇒ Length (l) is doubled & Area of cross section (A) is halved.l becomes 2l & A becomes 2A R=P AL now take l=2l,A= 2A
⇒ Length (l) is doubled & Area of cross section (A) is halved.l becomes 2l & A becomes 2A R=P AL now take l=2l,A= 2A
⇒ Length (l) is doubled & Area of cross section (A) is halved.l becomes 2l & A becomes 2A R=P AL now take l=2l,A= 2A
⇒ Length (l) is doubled & Area of cross section (A) is halved.l becomes 2l & A becomes 2A R=P AL now take l=2l,A= 2A R=
⇒ Length (l) is doubled & Area of cross section (A) is halved.l becomes 2l & A becomes 2A R=P AL now take l=2l,A= 2A R= A/2
⇒ Length (l) is doubled & Area of cross section (A) is halved.l becomes 2l & A becomes 2A R=P AL now take l=2l,A= 2A R= A/2P2l
⇒ Length (l) is doubled & Area of cross section (A) is halved.l becomes 2l & A becomes 2A R=P AL now take l=2l,A= 2A R= A/2P2l
⇒ Length (l) is doubled & Area of cross section (A) is halved.l becomes 2l & A becomes 2A R=P AL now take l=2l,A= 2A R= A/2P2l =4P
⇒ Length (l) is doubled & Area of cross section (A) is halved.l becomes 2l & A becomes 2A R=P AL now take l=2l,A= 2A R= A/2P2l =4P A
⇒ Length (l) is doubled & Area of cross section (A) is halved.l becomes 2l & A becomes 2A R=P AL now take l=2l,A= 2A R= A/2P2l =4P AL
⇒ Length (l) is doubled & Area of cross section (A) is halved.l becomes 2l & A becomes 2A R=P AL now take l=2l,A= 2A R= A/2P2l =4P AL
⇒ Length (l) is doubled & Area of cross section (A) is halved.l becomes 2l & A becomes 2A R=P AL now take l=2l,A= 2A R= A/2P2l =4P AL ⇒4R
⇒ Length (l) is doubled & Area of cross section (A) is halved.l becomes 2l & A becomes 2A R=P AL now take l=2l,A= 2A R= A/2P2l =4P AL ⇒4RResistance becomes 4 times
⇒ Length (l) is doubled & Area of cross section (A) is halved.l becomes 2l & A becomes 2A R=P AL now take l=2l,A= 2A R= A/2P2l =4P AL ⇒4RResistance becomes 4 times1) Resistivity does not depend on its length 02 Area.
⇒ Length (l) is doubled & Area of cross section (A) is halved.l becomes 2l & A becomes 2A R=P AL now take l=2l,A= 2A R= A/2P2l =4P AL ⇒4RResistance becomes 4 times1) Resistivity does not depend on its length 02 Area.Hence, it does not change.
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Explanation:
⇒ Length (l) is doubled & Area of cross section (A) is halved.
l becomes 2l & A becomes A/2
R=P L/A
now take l=2l,A= A/2
R=P2l/A/2 =4P
L/A ⇒4R
Resistance becomes 4 times
1) Resistivity does not depend on its length 02 Area.
Hence, it does not change.
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