The length of a cuboid is 4m, width is 5 M and height is 12 m. What is its volume and surface area?
Answers
Answered by
12
Volume of cuboid = lbh
= 4×5×12
=240 m
Total surface area of the cuboid = 2(lb+bh+hl)
=2(20+60+48)
=2(128)
=256m
= 4×5×12
=240 m
Total surface area of the cuboid = 2(lb+bh+hl)
=2(20+60+48)
=2(128)
=256m
Answered by
4
Length=4m
Width=5m
height=12m
Volume=l×b×h
=4×5×12=240m^3
TSA=2(lb+bh+hl)
=2(4×5+5×12+12×4)
=2(20+60+48)
=2(128)=256m^2.
Width=5m
height=12m
Volume=l×b×h
=4×5×12=240m^3
TSA=2(lb+bh+hl)
=2(4×5+5×12+12×4)
=2(20+60+48)
=2(128)=256m^2.
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