Question

The length of a cylinder is measured with a meter rod having least count 0.1cm. Its diameter is measured with Vernier calipers having least count 0.01cm. Given that length is 5.0cm and radius is 2 cm. Find the percentage error in the calculated value of the volume. answer: 3%

Answer 1

Answer:

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Answer 2

$volume \: of \: cyllinder \: v = \pi {r}^{2} l$

$∴percentage \: error \: in \: volume$

$= > \frac{ \triangle v}{v} \times 100 = \frac{2 \triangle \: r}{r} \times 100 + \frac{ \triangle \: l}{l} \times 100$

$= 2( \frac{0.01}{2.0} ) \times 100 + \frac{0.1}{5.0} \times 100$

$= (1 + 2) = 3$

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