The length of a cylindrical pipe of iron is 10 m. Its inner radius is 55 cm and the thickness of iron is 2 cm. Find the volume of iron used in the pipe.
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Answer:
0.704m³
Explanation:
Length=h=10m
=1000cm
Inner radius=55cm(R2)
Outer Radius=(55+2)=57cm(R1)
Volume of iron used=π(R1²-R2²)×h
=π(57²-55²)×1000
=π(3249-3025)×1000
=π(224×1000)
=22/7×224000
=22×32000
=704000cm³=0.704m³
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