Question

the length of a diagonal of a quadrilateral is 14cm and the perpendicular from the opposite vertices on the diagonal are 6cm and 8cm long then the area of quadrilateral​

Answer 1

GivEn:

• Heights = 6cm and 8cm
• Diagonal = 14cm

To Find:

• Area of the Quadrilateral?

Formula to be Used:

$\\ \bigstar{\underline{\boxed{\sf\pink{Area_{(Quadrilateral)} = \dfrac{1}{2} (h_{1} + h_{2} ) \times d }}}}$

Where as:

• h¹ = 1st Height
• h² = 2nd Height

Solution:

After putting Values in Formula to get the area of the Quadrilateral;

⟹ ½ × (h¹ + h²) × d

⟹ ½ × (6 + 8) × 14

⟹ ½ × (14) × 14

⟹ 98 cm²

Hence,

The area of the Quadrilateral is 98cm².

Remarks:

• D = Diagonal
• h = Height

• A Quadrilateral is a polygon with 4 sides and 4 corners.

Answer 2

Answer:

GivEn:

Heights = 6cm and 8cm

Diagonal = 14cm

To Find:

Area of the Quadrilateral?

Formula to be Used:

\begin{gathered} \\ \bigstar{\underline{\boxed{\sf\pink{Area_{(Quadrilateral)} = \dfrac{1}{2} (h_{1} + h_{2} ) \times d }}}} \\ \end{gathered}

★

Area

(Quadrilateral)

=

2

1

(h

1

+h

2

)×d

Where as:

h¹ = 1st Height

h² = 2nd Height

Solution:

After putting Values in Formula to get the area of the Quadrilateral;

⟹ ½ × (h¹ + h²) × d

⟹ ½ × (6 + 8) × 14

⟹ ½ × (14) × 14

⟹ 98 cm²

Hence,

The area of the Quadrilateral is 98cm².

Remarks:

D = Diagonal

h = Height

A Quadrilateral is a polygon with 4 sides and 4 corners.