Question

The length of a diagonal of a quadrilateral
shaped field is 48 m and the lengths of
perpendiculars dropped on it from the
remaining opposite vertices are 16 m and
26 m. Find the area of the field.​

Answer 1

Answer:

1) area of triangle = 1/2bh = 48x16/2=384m2

2)area of triangle = 1/2bh

= 48x26/2=624m2

Total = 1008m2

Answer 2

Answer: Mensuration:

Mensuration is the branch of mathematics which concerns itself with the measurement of Lengths, areas & volume of different geometrical shapes or figures.

Plane Figure: A figure which lies in a plane is called a plane figure.

For e.g:  a rectangle, square, a rhombus, a parallelogram, a trapezium.

Perimeter:

The perimeter of a closed plane figure is the total length of its boundary.

In case of a triangle or a polygon the perimeter is  the sum of the length of its sides.

Unit of perimeter is a centimetre  (cm), metre(m) kilometre(km) e.t.c

Area: The area of the plane figure is the measure of the surface enclose by its boundary.

The area of a triangle are a polygon is the measure of the surface enclosed by its sides.

A square centimetre (cm²) is generally taken at the standard unit of an area. We use square metre (m²) also for the units of area.

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Solution;

Area of quadrilateral

= Area of Triangle ABC + Area of Triangle ADC

Area of Triangle =(1/2) ×Height ×Base

In Triangle ABC

Base (AC) =24 m, height (h1) =13 m

Area of Triangle ABC =(1/2) ×13×24= 156 m²

Area of Triangle ABC =156 m²

In Triangle ADC

Base (AC) =24 m, height (h2) =8 m

 

Area of Triangle ADC

=(1/2) ×8×24= 96 m²

Area of Triangle ADC =96 m²

Area of the field = Area of Triangle ABC + Area of Triangle ADC

=156 + 96 = 252 m²

Area of the field = 252 m²

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Hope this will help you...

Step-by-step explanation: