the length of a diagonal of a rhombus are in inches two consecutive integers the area of rhombus is 210 m square find its perimeter in inches
Answers
Answer:
40 cm
Step-by-step explanation:
A rhombus is a parallelogram with all of its sides being equal. A square is a rhombus with all of the angles being equal as well as all of the sides. Both squares and rhombuses have perpendicular diagonal bisectors that split each diagonal into 2 equal pieces, and also splitting the quadrilateral into 4 equal right triangles.
With this being said, we know the Pythagorean Theorem would work great in this situation, using half of each diagonal as the two legs of the right triangle.
(8cm)2+(6cm)2=h2 where h is the hypotenuse.
h2=100 cm2 --> h=10cm
We find the hypotenuse to be 10cm. Since the hypotenuse of each triangle is a side of the rhombus, we have found what we need to find the perimeter.
Each side is the same, so we add all 4 sides to find the perimeter.
10+10+10+10=40 cm.
hope it helps you
please mark me brainliest
Given,
The diagonals of rhombus are in inches two consecutive integers.
The area of rhombus is 210 m square
To find,
It's perimeter in inches.
Solution:
The area of rhombus = 210 m² = 210*(39.37inch) ²
The area of rhombus = 327,979.659
Hence,
(1/2) *d1*d2 = 327,979.659
As the diagonals are two consecutive numbers,
d1 = x
d2 = x+1
It gives,
(1/2) *x*(x+1)= 327,979.659
= 327,979.659
x²+x = 327,979.659*2
x²+x = 655,959.318.
Perimeter = 4a.
#SPJ2