Question

the length of a diagonal of a square is
$\sqrt[10]{2}$
find its area​

Answer 1

Answer:

Here is your answer

area=100cm^2 & perimeter=40cm

diagonal of square=10root2cm

let one of its side be a. Therefore a^2+a^2=200

therefore a=10

are=a^2=100 and perimeter=4a=40

Step-by-step explanation:

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