Math, asked by ruhi6897, 1 year ago

The length of a hall exceeds its breadth by 12m if the perimeter of the hall is 76m find the cost of carpeting it at ₹4 per m2

Answers

Answered by kuzhale
40

Answer:

length = 25 m

breadth= 13 m

area = 325 sq.m

cost of carpeting = ₹1300.

Step-by-step explanation:

let x be the breadth

then length is x +12

now,perimeter=2(l+b)=76

so, 2(x + 12+ x)=76

2x+ 12=76/2=38

2x=38-12=26

x=26/2=13

so,breadth =13m

and length =13+12=25m

now area = length x breadth

= 25 x 13=325 sq.m

so,cost of carpeting = 325 x 4

=₹1300.

Answered by Anonymous
13

Sol: Let the breadth of hall = xm

Length of hall = (x+12)m

Perimeter of Rectangle = 76 m

 = 2(l + b) = 76 \\  = 2(x + x + 12) = 76 \\  = 2(2x + 12) = 76 \\  = 2x + 12 =  \frac{76}{2}  \\  = 2x = 38 - 12 \\  = 2x = 26 \\  = x =  \frac{26}{2}  \\  = x = 13

So , Breadth = 13cm and length = (13 + 12) = 25cm

Area of hall = L × B

= 25 × 13

= 325 cm²

Cost of 1m² of Carpeting = Rs4

Cost of 156m² of Carpeting = Rs4 × 325 = Rs1300

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