Question

The length of a hall is 18m and its width is 13.5m.Find the least no. of sq. tiles,each of side 25cm, required to cover the floor of the hall leaving a margin of width 1.5m all around. Also find the cost of the tiles required at the rate of ₹6 per tile.

Answer 1

et ABCD be the hall.
Now, AB = 18 m = 1800 cm    ;    BC = 13.5 m = 1350 cm

Length of each side of the square tile, s = 25 cm

area of each square tile = s × s = 25 × 25 = 625 cm2

(1).

Area of the hall  = length × breadth
area of the floor =  AB × BC
                         =  1800 × 1350 = 2430000 cm2

no. of square tiles needed to cover the floor = area of floorarea of each tile

                                                                 = 2430000625 = 3888

cost of each tile = Rs 6.00
so, cost of 3888 tiles = Rs (6 × 3888) = Rs 23328

(2).

Length of rectangle ABCD, AB = 1800 m
breadth of rectangle ABCD, BC = 1350 m
width of the margin = 1.5 m = 150 cm

Now,
length of rectangle EFGH , EF = AB - 2(width of margin) = 1800 - 300 = 1500 cm

breadth of rectangle EFGH , FG = BC - 2(width of the margin) = 1350 - 300 = 1050 cm

Area of the rectangle EFGH  = length × breadth
                    area of the floor =  EF × FG
                                             =  1500 × 1050 = 1575000 cm2

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no. of square tiles needed to cover the floor = area of rectangle EFGHarea of each square tile

                                                                   = 1575000625 = 2520

cost of each tile = Rs 6.00
so, cost of 2520 tiles = Rs (6 × 2520)
= Rs 15120

Don't forget to mark it as brainly

Answer 2

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