The length of a hall is 8 m more than its breadth. If the perimeter of the hall is 40 m, find the cost
of laying a carpet at the cost of 7 12 per sq. m.
Answers
Step-by-step explanation:
Let the breadth be : X m
then,the length be : (X+8)m
perimeter: 40m
2(length+breadth) = 40m
2(X+8+X) = 40m
2x+16+2x =40m
4x+16 = 40m
4x= 40-16
4x= 24
X= 24/4
X= 6
therefore,breadth=6m and length=6+8=14m
Area= length×breadth
= 14m×6m
= 84m²
cost of laying carpet is 84×12
= 1008/-
Required cost of laying the carpet is Rs₹ 1008.
Step-by-step explanation:
Perimeter of a rectangle = 2( length + breadth )
Here,
Length of the hall is 8 m more than its breadth. Let the breadth be a m, then length should be a + 8 m.
According to the question perimeter of hall is 49 m.
= > 2( a + a + 8 ) m = 40 m
= > ( 2a + 8 ) m = 20 m
= > 2a m = 20 m - 8 m
= > a m = 6 m
Thus, breadth of the hall is 6 m and length is 8 m + 6 m Or 14 m.
= > Area of the hall = length x breadth
= > 14 m x 6 m
= > 84 m^2
Thus,
= > cost of laying the carpet = area to be covered x rate of laying
= > cost of laying the carpet = 84 m^2 x 12 / m^2 = 1008 m^2.
Hence the required cost of laying the carpet is Rs₹ 1008.