Math, asked by shubhambanger007, 11 months ago


The length of a hypotenuse of a right triangle exceeds the length of its base by 2cm and exceeds
length of the altitude by 1 cm, then the length of each side of the triangle (in cm) is

Answers

Answered by vicky8764
1

Answer:

let the hypotenuse length be x cm

then

base = x-2 cm

altitude= x-1 cm

By pythagoras theorem

X2=(x-1)2+(x-2)2

X2=x2-2x+1+x2-4x+4

X2=2x2-6x+5

2x2-x2-6x+5=0

x2-6x+5=0

x2-x-5x+5=0

x(x-1)-5(x-1)=0

(x-1)(x-5)=0

then x= 1 or 5 cm

for 1 cm

base = 1-2=-1 which is not possible so x value is 5 cm

hypotenuse =5 cm

base= 5-2= 3 cm

altitude= 5-1 =4 cm

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