The length of a line segment is 10. If one end point is (2,-3) and the abscissa of the second end point is 10 , show that its ordinate is either 3 or -9
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The length of a line segment is 10. If one end point is (2,-3) and the abscissa of the second end point is 10 , show that its ordinate is either 3 or -9
Hey mate here's the Solution......
Solution.......
Here,
Coordinates are (2,-3) and
(10,y)
and x2 = 10 , y2 = y & x1= 2 and y1 = -3
By distance Formula....
√(x2-x1)²+(y2-y1)² = 10
√(10-2)²+(y+3)²
√8²+y²+9+6y = 10
64+9+y²+6y= 100
y²+6y= 100-73 = 27
y²-6y-27=0
we get an equation,
By solving it.....
y²-9y+3y-27=0
y(y-9)+3(y-9)= 0
(y-9)(y+3)= 0
By this.....
y-9=0 and y+3=0
y = 9 and y = -3
So, the value of y(ordinate) is 9 or -3
Hence Proved.....
The length of a line segment is 10. If one end point is (2,-3) and the abscissa of the second end point is 10 , show that its ordinate is either 3 or -9
Hey mate here's the Solution......
Solution.......
Here,
Coordinates are (2,-3) and
(10,y)
and x2 = 10 , y2 = y & x1= 2 and y1 = -3
By distance Formula....
√(x2-x1)²+(y2-y1)² = 10
√(10-2)²+(y+3)²
√8²+y²+9+6y = 10
64+9+y²+6y= 100
y²+6y= 100-73 = 27
y²-6y-27=0
we get an equation,
By solving it.....
y²-9y+3y-27=0
y(y-9)+3(y-9)= 0
(y-9)(y+3)= 0
By this.....
y-9=0 and y+3=0
y = 9 and y = -3
So, the value of y(ordinate) is 9 or -3
Hence Proved.....
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