Question

The length of a line segment is 13 units and the coordinates of one end point are (6,-7) if the ordinate of the other end point is -1 find the abscissa of the other point

Answer 1

absicca is 6 becase absicca is that which come first digit in 9 class in chapter 3

Answer 2

Answer:

The abscissa of the other point is either -5.53 or 17.53.

Step-by-step explanation:

The length of a line segment is 13 units and the coordinates of one end point are (6,-7).

The ordinate of the other end point is -1. Let the abscissa of the other point be x. So, the coordinates of point are (x,-1).

Distance formula:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

It is given that the distance between (6,-7) and (x,-1) is 13 units.

$13=\sqrt{(x-6)^2+(-1+7)^2}$

Square both the sides.

$169=x^2-12x+36+36$

$169=x^2-12x+72$

$0=x^2-12x-97$

Using quadratic formula:

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

Using quadratic formula we get

$x=\frac{12\pm \sqrt{(12)^2-4(1)(-97)}}{2(1)}$

$x\approx -5.53, 17.53$

Therefore the abscissa of the other point is either -5.53 or 17.53.