the length of a line segment is 13 units and the coordinates of one end point are (6,-7) if the ordinate of the other end point is -1 find the abscissa of the other point
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Let AB be the line segment
Therefore, A(6,-7) and B will be (x,-1)
as y-coordinate is called ordinate and x-coordinate is called abscissa.
By applying Distance Formula,
AB²=(x2-x1)²+(y2-y1)²
13²=(x-6)²+(-1+7)²
169=x²-12x+36+36
⇒x²-12x+72=169
⇒x²-12x-97=0
From here solve it urself.... CHEERS!!
Therefore, A(6,-7) and B will be (x,-1)
as y-coordinate is called ordinate and x-coordinate is called abscissa.
By applying Distance Formula,
AB²=(x2-x1)²+(y2-y1)²
13²=(x-6)²+(-1+7)²
169=x²-12x+36+36
⇒x²-12x+72=169
⇒x²-12x-97=0
From here solve it urself.... CHEERS!!
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