The length of a line segment is of 10 units and the coordinates of one endpoint are 2 - 3 if the abscissa of the other end is 10 find the coordinates of the other end
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10=√(10-2)²+(y+3)²
square root sign comes to LHS and becomes whole square
100=64+y²+6y+9
36=y²+6y+9
y²+6y=27
y²+6y-27=0
y²-3y+9y-27=0
y(y-3)+9(y-3)=0
y= -9 or y=3
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