Question

the length of a line segment is of 10 units n the coordinates of one end point are (2, -3). If the abscissa of the other end is 10, find the ordinate of the other end.

Answer 1

Let ordinate be y,

Here AB=10,A=(2,-3),B=(10,y)

AB=root of (10-2)square+(y+3)square

10square =64+T-square+6y+9

Ysauqre+6y-27=0

(Y-3)(y+9)=0

Y=3 or y =-9